SOLUTION: Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 p
Algebra ->
Customizable Word Problem Solvers
-> Unit conversion
-> SOLUTION: Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 p
Log On
Question 296495: Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Tim and Judy mix two kinds of feed for pedigreed dogs. They wish to make 54 pounds of feed worth $0.28 per pound by mixing one kind worth $0.24 per pound with another worth $0.42 per pound. How many pounds of the cheaper kind should they use in the mix?
let x pounds of cheaper feed be required
the other one required will be 54-x
0.24*(x)+0.42(54-x)=0.28 * 54
0.24x +22.68 -0.42x =15.12
0.24x-0.42x=15.12-22.68
0.18x= 7.56
x=7.56 / 0.18
x=42 lbs- the cheaper variety
