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Question 296161: 2m^2+12m+5=0
Answer by persian52(161)   (Show Source):
You can put this solution on YOUR website! 2m^(2)+12m+5=0
Use the quadratic formula to find the solutions. In this case, the values are a=2, b=12, and c=5.
m=(-b\~(b^(2)-4ac))/(2a) where am^(2)+bm+c=0
Substitute in the values of a=2, b=12, and c=5.
m=(-12\~((12)^(2)-4(2)(5)))/(2(2))
Simplify the section inside the radical.
m=(-12\2~(26))/(2(2))
Simplify the denominator of the quadratic formula.
m=(-12\2~(26))/(4)
Simplify the expression to solve for the + portion of the \.
m=(-6+~(26))/(2)
Simplify the expression to solve for the - portion of the \.
m=(-6-~(26))/(2)
The final answer is the combination of both solutions.
m=(-6+~(26))/(2),(-6-~(26))/(2)_mAPPR-0.45,-5.55
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