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Question 296156: (2x-1)(x+3)=99
Answer by persian52(161)   (Show Source):
You can put this solution on YOUR website! Detail Explanation
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(2x-1)(x+3)=99
Multiply each term in the first group by each term in the second group using the FOIL method. FOIL stands for First Outer Inner Last, and is a method of multiplying two binomials. First, multiply the first two terms in each binomial group. Next, multiply the outer terms in each group, followed by the inner terms. Finally, multiply the last two terms in each group.
(2x^(2)+5x-3)=99
Remove the parentheses around the expression 2x^(2)+5x-3.
2x^(2)+5x-3=99
To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side.
2x^(2)+5x-102=0
Find the factors such that the product of the factors is the trinomial 2x^(2)+5x-102. This can be done by trial and error and checked using the FOIL method of simplifying polynomials.
(2x+17)(x-6)=0
Set each of the factors of the left-hand side of the equation equal to 0.
2x+17=0_x-6=0
Since 17 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 17 from both sides.
2x=-17_x-6=0
Divide each term in the equation by 2.
x=-(17)/(2)_x-6=0
Set each of the factors of the left-hand side of the equation equal to 0.
x=-(17)/(2)_x-6=0
Since -6 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 6 to both sides.
x=-(17)/(2)_x=6
The complete solution is the set of the individual solutions.
Answer: x=-(17)/(2),6
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