SOLUTION: suppose it costs $8 to dig a hole 1 foot deep, $6.40 for the second foot, $5.12 for the third foot, and so forth. How much would it cost to dig a 5-foot deep hole?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: suppose it costs $8 to dig a hole 1 foot deep, $6.40 for the second foot, $5.12 for the third foot, and so forth. How much would it cost to dig a 5-foot deep hole?      Log On

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Question 296000: suppose it costs $8 to dig a hole 1 foot deep, $6.40 for the second foot, $5.12 for the third foot, and so forth. How much would it cost to dig a 5-foot deep hole?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
8+6.40+5.12+ 4.096+3.2678=26.8928
c(h)=(.8)^4*8+(.8)^3*8+(.8)^2*8+(.8)^1*8+(.8)^0*8
c(h)=8*(.8^4+.8^3+.8^3+.8^2+.*1+.8^0)
8*3.3616=26.8928=$26.90 round up