SOLUTION: find two consecutive negative integers whose product is 132

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Question 295590: find two consecutive negative integers whose product is 132
Answer by mananth(16946) About Me  (Show Source):
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let one integer be x
the other integer will be x+1
x(x+1)=132
x^2 +x-132=0
x^2+12x-11x-132=0
X(X+12)-11(X+12)=0
(X-11)(X+12)=0
X=11 OR -12

SINCE THE NUMBERS ARE NEGATIVE THE NUMBERS ARE -12 & -11