SOLUTION: Solving Exponential Equations Using Logarithms? 2^x = 30 5^x - 1 = 3^x 3.53^(x+1) = 65.4 16^(x - 4) = 3^(3 - x) 7^(x - 2) = 5^x

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Solving Exponential Equations Using Logarithms? 2^x = 30 5^x - 1 = 3^x 3.53^(x+1) = 65.4 16^(x - 4) = 3^(3 - x) 7^(x - 2) = 5^x      Log On


   

Question 295511: Solving Exponential Equations Using Logarithms?
2^x = 30
5^x - 1 = 3^x
3.53^(x+1) = 65.4
16^(x - 4) = 3^(3 - x)
7^(x - 2) = 5^x
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
2^x = 30
log[2](2^x)=log[2](30)
x=4.90689...
.
Ed