Question 29546: Solve using the multiplication and the addition principles. Ex.8(2t+1)>4(7t+7) Found 2 solutions by sdmmadam@yahoo.com, JimMarshall:Answer by sdmmadam@yahoo.com(530) (Show Source):
You can put this solution on YOUR website! 8(2t+1)>4(7t+7)
Dividing by 4>0
(Dividing by a positive quantity does not alter the inequality and therefore greater than remains greater than)
2(2t+1>7t+7
4t+2 > 7t +7
4t-7t > 7-2
(grouping like terms by transferring terms,change side then change sign)
-3t > 5
(Dividing by (-3) and dividing by a negative quantity alters the inequality and therefore greater than becomes less than)
t < 5/(-3)
That is t< (-5/3)
You can put this solution on YOUR website! 8(2t+1)>4(7t+7)
Dividing by 4>0
(Dividing by a positive quantity does not alter the inequality and therefore greater than remains greater than)
2(2t+1>7t+7
4t+2 > 7t +7
4t-7t > 7-2
(grouping like terms by transferring terms,change side then change sign)
-3t > 5
(Dividing by (-3) and dividing by a negative quantity alters the inequality and therefore greater than becomes less than)
t < 5/(-3)
That is t< (-5/3) Ans
(
