SOLUTION: You randomly choose a piece of hard candy from a jar containing 5 peppermint, 10 butterscotch, and 7 cinnamon candies. You decide that you don't want the piece that you chose, so y

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: You randomly choose a piece of hard candy from a jar containing 5 peppermint, 10 butterscotch, and 7 cinnamon candies. You decide that you don't want the piece that you chose, so y      Log On


   



Question 295405: You randomly choose a piece of hard candy from a jar containing 5 peppermint, 10 butterscotch, and 7 cinnamon candies. You decide that you don't want the piece that you chose, so you put it back and randomly choose another piece. Find the probability that you choose a cinnamon candy first and a butterscotch candy second. Thanks!
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!


There are 22 pieces of candy in the jar.

Since "AND" means "multiply",

P(cinnamon first AND butterscotch second)

= %287%2F22%29%2A%2810%2F22%29=35%2F242

Edwin