Question 295198: Hello,
I am using the pythagorean theorem to obtain a polynomial equation. This is the scenario:
A right angle has a hypotenuse that is 13 inches long. If one leg is 2 inches more than twice the other leg, find the length of the longer leg of the right triangle.
I have attempted this using the following information, however I am relatively sure that there is a flaw.
leg 1 = x
leg 2 = 2x + 2
hypotenuse = x + 13
Applying the pythagorean theorem A^2 + B^2 = C^2 I have formed this equation.
(X)^2 + (2x + 2)^2 = (x + 13)^2
My answer should be 12 inches but I cannot figure this out.....PLEASE HELP!!!
Thanks,
LW
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! hypotenuse is 13 not x+13
Also don't switch from X to x in the same equation. Use one or the other.
Angles don't have hypotenuse. Triangles do.
x^2 + (2x + 2)^2 = (13)^2
This a special right triangle 5,12,13
x=5
2x+2=12
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