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Question 29515: Can you help me determine the slope and y-intercept point of y=x/2-8?
Answer by sdmmadam@yahoo.com(530)   (Show Source):
You can put this solution on YOUR website! the slope and y-intercept point of y=x/2-8?
y=x/2-8
That is y = (1/2)x+(-8) ----(1)
(1) is in the form y =(m)x +b ----(*) which is called the slope and y-intercept form of an equation. Here m is the slope of the line and b is the y-intercept
Therefore in (1),the slope = (1/2) and the y-intercept = (-8)
Slope positive implies the line's journey is from the I quadrant to the III quadrant (as the line makes an acute angle with the x-axis) and since the
y-intercept is negative,the line travels via the IV quadrant.
It cuts off a length = 8 units on the y-axis below the origin.
Supposing the line meets the y-axis at P then P is on the y-axis with P below the x-axis and OP = 8 unints
Therefore the point P has co-ordinates (0,-8)
Note: How do we recognise the slope to be (1/2) and the y-intercept to be (-8)
The rule is when the coefficient of y is 1 (the value one) on one side of the equation,(say the LHS)then the coefficient of x on the other side of the equation(RHS) is the slope of the line and the free constant on the other side (RHS)is the y-intercept of the line.
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