SOLUTION: Identify the equation of the circle that has its center at (-15, 36) and passes through the origin.

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Identify the equation of the circle that has its center at (-15, 36) and passes through the origin.       Log On


   

Question 295115: Identify the equation of the circle that has its center at (-15, 36) and passes through the origin.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt(15^2+36^2)=39
(x+15)^2+(y-36)^2=39^2