SOLUTION: The diameters of oranges in a certain orchard are normally distributed with a mean of 4.85 inches and a standard deviation of 0.40 inches. 1). What percentage of the oranges in

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Question 295016: The diameters of oranges in a certain orchard are normally distributed with a mean of 4.85 inches and a standard deviation of 0.40 inches.
1). What percentage of the oranges in this orchard have diameters less than 6.3 inches?

2). What percentage of the oranges in this orchard are larger than 4.75 inches?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The diameters of oranges in a certain orchard are normally distributed with a mean of 4.85 inches and a standard deviation of 0.40 inches.
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1). What percentage of the oranges in this orchard have diameters less than 6.3 inches?
z(6.3) = (6.3-4.85)/0.4 = 3.625
P(x<6.3) = P(z< 3.625) = normalcdf(-100,3.625) = 0.9999..
2). What percentage of the oranges in this orchard are larger than 4.75 inches?
z(4.75) = (4.75-4.85)/0.4 = -0.25
P(x > 4.75) = P(z > -0.25) = normalcdf(-0.25,100) = 0.5987..
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Cheers,
Stan H.