SOLUTION: x^2-y^2=3 2x+y=3

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: x^2-y^2=3 2x+y=3      Log On


   

Question 294997: x^2-y^2=3
2x+y=3
Found 2 solutions by helpnalgebra, Alan3354:
Answer by helpnalgebra(91) About Me  (Show Source):
You can put this solution on YOUR website!
x^(2)-y^(2)=32x+y=3
-y^(2)=-x^(2)
y^(2)=x^(2)
y=(x^(2))^((1)/(2))
y=(x^(2*(1)/(2)))
y=(x^(1*1))
y=(x)
y=x answer

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x^2-y^2=3
2x+y=3 --> y = -2x + 3
----------
Sub for y into the 1st eqn:
x%5E2+-+%28-2x%2B3%29%5E2+=+3
-3x%5E2+%2B+12x+-+9+=+3
3x%5E2+-+12x+%2B+12+=+0
x%5E2+-+4x+%2B+4+=+0
%28x-2%29%5E2+=+0
---------------------
x = 2, y = -1