SOLUTION: How do I solve complex number problems like 6+5i/-2i, 2/7-8i, 3-i/2-i, and 2-4i/1+3i?

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: How do I solve complex number problems like 6+5i/-2i, 2/7-8i, 3-i/2-i, and 2-4i/1+3i?      Log On


   

Question 294908: How do I solve complex number problems like 6+5i/-2i, 2/7-8i, 3-i/2-i, and 2-4i/1+3i?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
For division by a complex number, multiply numerator and denominator by the complex conjugate of the divisor. I'll show you one.
%286%2B5i%29%2F%28-2i%29=%28%286%2B5i%29%2F%28-2i%29%29%2A%28%282i%29%2F%282i%29%29
%286%2B5i%29%2F%28-2i%29=%2812i%2B10i%5E2%29%2F%28-4i%5E2%29
%286%2B5i%29%2F%28-2i%29=%2812i-10%29%2F%284%29
%286%2B5i%29%2F%28-2i%29=%28-10%2F4%29%2B12i%2F4
%286%2B5i%29%2F%28-2i%29=%28-5%2F2%29%2B3i