SOLUTION: Hi, I need help with the following please. Any assistance would be really appreciated! Solve: log5(-2x) ----------- --- = 2 log5(x+1)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Hi, I need help with the following please. Any assistance would be really appreciated! Solve: log5(-2x) ----------- --- = 2 log5(x+1)      Log On


   

Question 294870: Hi, I need help with the following please. Any assistance would be really appreciated!
Solve:
log5(-2x)
--------------- = 2
log5(x+1)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log5(-2x)
--------------- = 2
log5(x+1)
---------------------------------
log%285%2C%28-2x%29%29+=+2log%285%2C%28x%2B1%29%29
log%285%2C%28-2x%29%29+=+log%285%2C%28x%2B1%29%5E2%29
-2x+=+%28x%2B1%29%5E2
x%5E2+%2B+4x+%2B+1+=+0
x = -2 +/- sqrt(3)
-------------
The -2-sqrt(3) won't work as it will give the log of a negative number.