Question 294635: F(x)= -5(x-2)^2(x+3)^3 Find the leading term and the degree
Answer by helpnalgebra(91)   (Show Source):
You can put this solution on YOUR website! f(F,x)=-5(x-2)^(2)(x+3)^(3)
(0)=-5(x-2)^(2)(x+3)^(3)
-5(x-2)^(2)(x+3)^(3)=(0)
(x-2)^(2)=0_(x+3)^(3)=0
(x-2)^(2)=0
x-2=0
x=2
(x+3)^(3)=0
x+3=0
x=-3
x=2,-3
y=-5((0)-2)^(2)((0)+3)^(3)
y=-5(0-2)^(2)((0)+3)^(3)
y=-5(-2)^(2)((0)+3)^(3)
y=-5(-2)^(2)(0+3)^(3)
y=-5(-2)^(2)(3)^(3)
y=(-5*(-2)(-2)(3)^(3))
y=(-5*(4)(3)^(3))
y=(-5*4(3)^(3))
y=(-5*(4)*3^(3))
y=(-5*(4)*27)
y=(-135(4))
Solve the equation.
y=-540
These are the x and y intercepts of the equation y=-5(x-2)^(2)(x+3)^(3).
x=2,-3, y=-540
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