SOLUTION: Just need some help setting this one up please, I believe it should be a quadratic equation but not quite sure. ok here it is: A ball is thrown vertically upward from the ground. I

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Just need some help setting this one up please, I believe it should be a quadratic equation but not quite sure. ok here it is: A ball is thrown vertically upward from the ground. I      Log On

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Question 29459: Just need some help setting this one up please, I believe it should be a quadratic equation but not quite sure. ok here it is: A ball is thrown vertically upward from the ground. Its distance in feet from the ground in t seconds is -16t^2+112t. After how many seconds will the ball be 160 feet from the ground? I was thinking it should be set up as -16t^2+112t-160=0 Thanks for your help!!
Answer by longjonsilver(2297) About Me  (Show Source):
You can put this solution on YOUR website!
distance = -16t%5E2%2B112t, so we have
160+=+-16t%5E2%2B112t

so 0+=+-16t%5E2%2B112t-160
or +16t%5E2-112t%2B160+=+0+
or +t%5E2-7t%2B10+=+0+

then factorise... 5 and 2 etc.

you will get 2 answers. What does getting 2 times mean physically?

jon.