SOLUTION: if a ball is thrown directly upward with a velocity of 20 feet per second, its heigh (in feet) after t seconds is given by y= 20t - 16t^2. what is the max height attained by the ba

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: if a ball is thrown directly upward with a velocity of 20 feet per second, its heigh (in feet) after t seconds is given by y= 20t - 16t^2. what is the max height attained by the ba      Log On


   

Question 29455: if a ball is thrown directly upward with a velocity of 20 feet per second, its heigh (in feet) after t seconds is given by y= 20t - 16t^2. what is the max height attained by the ball?
Answer by Paul(988) About Me  (Show Source):
You can put this solution on YOUR website!
Differenate the function:

dy%2Fdx=20t-16t%5E2
dy%2Fdx=20-32t
-32t=-20
t=0.625

lim 20t-16t%5E2 = 6.25
t->0.625


Hence, the maxium height reached was 6.25ft.
Paul.