SOLUTION: I have a piece of cardboard that is twice as long as it is wide. If I cut a 2-inch by 2-inch square from each corner and fold up the resulting flaps, I get a box with a volume of 6

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: I have a piece of cardboard that is twice as long as it is wide. If I cut a 2-inch by 2-inch square from each corner and fold up the resulting flaps, I get a box with a volume of 6      Log On

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Question 294493: I have a piece of cardboard that is twice as long as it is wide. If I cut a 2-inch by 2-inch square from each corner and fold up the resulting flaps, I get a box with a volume of 6720 cubic inches. What are the dimensions of the cardboard?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
W=2L
(W-4)(L-4)*2=6,720
(2L-4)(L-4)*2=6,720
(2L^2-4L-8L+16)*2=6,720
4L^2-24L+32-6,720=0
4L^2-24L-6,688=0
4(L^2-6L-1,672)=0
4(L-44)(L+38)=0
L-44=0
L=44 INCHES FOR THE LENGTH OF THE CARDBOARD.
W=2*44=88 INCHES IS THE WIDTH OF THE CARDBOARD.
PROOF:
(88-4)(44-4)*2=6,720
84*40*2=6,720
6,720=6,720