SOLUTION: log base 2(y+2)-log base 2(y-2)=1

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Question 294342: log base 2(y+2)-log base 2(y-2)=1
Found 2 solutions by Alan3354, richwmiller:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log base 2(y+2)-log base 2(y-2)=1
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log%282%2C%28y%2B2%29%29+-+log%282%2C%28y-2%29%29+=+1
log%282%2C%28%28y%2B2%29%2F%28y-2%29%29%29+=+1
(y+2)/(y-2) = 2
y+2 = 2y-4
2 = y-4
y = 6

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
y=6
log2(6+2)-log2(6-2)=1
log2(8)-log2 (4)=1
3-2=1
x-z=1
x=z+1
2^x=(y+2)
2^z=(y-2)
2^(z+1)=(y+2)