SOLUTION: logx + log(x-3)=1

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Question 294210: logx + log(x-3)=1
Answer by nyc_function(2741) About Me  (Show Source):
You can put this solution on YOUR website!
1. Write as one log isolated on one side.
log[x(x - 3)] = 1
2. Write in exponential form.
Base = 10, exponent = 1
10^1 = x(x - 3)
3. Solve for x.
10 = x^2 - 3x
0 = x^2 - 3x - 10
0 = (x - 5)(x + 2)
Can you finish now?