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Question 294017: 1 x+4
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x^2-16 x^2-3x-4
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1 x+4
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x^2-16 x^2-3x-4
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Factor the denominators:
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1/[(x-4)(x+4)] - (x+4)/[(x-4)(x+1)]
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lcd = (x+1)(x-4)(x+4)
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Rewrite each fraction with the lcd as its denominator:
(x+1)/lcd - (x+4)^2/lcd
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Combine the numerators over the lcd:
[x+1 - (x+4)^2]/lcd
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Simplify the numerator:
[x+1 -x^2 - 8x - 16]/lcd
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Rearrange:
[-(x^2 +7x + 15)]/[(x+1)(x^2-16)]
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Cheers,
Stan H.
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