SOLUTION: There are thirty-five (35) members in the Travel Club. Four (4) people will be chosen to win a vacation. How many ways can the four (4) be chosen if all four will win a trip to Las

Algebra ->  Probability-and-statistics -> SOLUTION: There are thirty-five (35) members in the Travel Club. Four (4) people will be chosen to win a vacation. How many ways can the four (4) be chosen if all four will win a trip to Las      Log On


   



Question 293957: There are thirty-five (35) members in the Travel Club. Four (4) people will be chosen to win a vacation. How many ways can the four (4) be chosen if all four will win a trip to Las Vegas?
I have no idea how to do these types of problems! Help?!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There are thirty-five (35) members in the Travel Club. Four (4) people will be chosen to win a vacation. How many ways can the four (4) be chosen if all four will win a trip to Las Vegas?
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When you are asked to count groups you should use "combinations".
When you are asked to arrange individuals (or groups) you should
use "permutations".
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Your Problem:
# of groups of 4 when selecting from a population of 35:
35C4 = (35*34*32*31)/(1*2*3*4) = 52,360
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Cheers,
Stan H.
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