SOLUTION: Please solve: log8-log2x=-1

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Question 293651: Please solve: log8-log2x=-1
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
log8-log2x=-1
log(2x) = log(8)+1 = log(80)
2x = 80
x = 40

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log8-log2x=-1
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log[8/(2x)] = -1
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log[4/x] = -1
---
4/x = 10^-1
x/4 = 10
x = 40
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Cheers,
Stan H.