Question 29357: A trapezoid is formed by lines with the following equations
2x+4y=16 x=4 x=0 y=0
Find the area of the trapezoid.
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! area of trapezoid is (h/2)(a+b) where h is the perpendicular distance between the 2 parallel sides, which have lengths a and b.
2 parallel lengths are those defined by x=0 and x=4... how long are they though? well they intersect the line 2x+4y=16, so...
when x=0, 2x+4y=16 gives 2(0)+4y=16
0 + 4y = 16
4y = 16
y = 16/4
y = 4
when x=4, 2x+4y=16 gives 2(4)+4y=16
8 + 4y = 16
4y = 8
y = 8/4
y = 2
So, the 2 lengths for a and b are 4 and 2
The perpendicular length between them is 4... the distance between x=0 and x=4
So, put these values into the formula above.
jon.
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