SOLUTION: A reduction of 10% in the price of tea enables a dealer to purchage 25kg more tea for Rs 22500.What is the reduced price per kg of tea? What was the original price per kg?

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Question 29341: A reduction of 10% in the price of tea enables a dealer to purchage 25kg more tea for Rs 22500.What is the reduced price per kg of tea? What was the original price per kg?
Found 3 solutions by josmiceli, josgarithmetic, greenestamps:
Answer by josmiceli(19441)   (Show Source):
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p = original price of tea in Rs/kg
.1p = the reduction in the price of tea in Rs/gk
p - .1p = the REDUCED price of tea in Rs/kg
p - .1p = (1 - .1)p = .9p
(.1p Rs/kg)(25 kg) = 22500 Rs
2.5p Rs = 22500 Rs
p = 9000 Rs/kg the original price
.9p = 8100 Rs/kg the reduced price

Answer by josgarithmetic(39617)   (Show Source):
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PRICE QUANT. COST ( in Rs) Normal Price 10x 22500/(10x) 22500 Reduced Price 9x 22500/(9x) 22500 Difference 25

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Original price was .

check:

Answer by greenestamps(13200)   (Show Source):
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For the fixed price of Rs 22500, if the price is reduced by a factor of 9/10 then the amount he can buy for that price increases by a factor of 10/9.

Let x be the number of kg he could buy at the original price. Then

At the original price, he could buy x=225 kg of tea; at the reduced price he can buy x+25=250 kg.

The original price per kg was Rs 22500/225 = Rs 100.

The reduce price per kg was Rs 22500/250 = Rs 90. (Or, the reduce price per kg was 90% of Rs 100, which is Rs 90.)

ANSWERS:
reduced price per kg: Rs 90
original price per kg: Rs 100