Question 29337: How do I solve the problem (4-i)^2+2(3-2i)-4. I need to perform the indicated operations and write the answer in standard form. HELP!
Answer by ikdeep(226)   (Show Source):
You can put this solution on YOUR website! (4-i)^2+2(3-2i)-4
1st solve (4-i)^2 with the identity (a-b)^2= a^2 + b^2 - 2ab...and we get
[(4)^2 + (i)^2 - 2(4)(i)] + 2(3-2i)-4
[16 + i^2 - 8i ] + 2(3-2i)-4
Now,lets solve the other part i.e..2(3-2i)-4....here is the simple multipication requried...
[16 + i^2 - 8i ] + 6 - 4i -4
or, 16 + i^2 - 8i + 6 - 4i -4
Now, put together the like variables ....we get..
i^2 - 8i-4i +16+6-4
i^2 -12i +22-4
i^2 -12i +18.......ANSWER
if further factorization is requried,,,,I suggest that you must 1st check the equation and then let me know...
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