Question 293309: What is the focus point of y= 1/4x^2+2?
I dont understand how to find the focus point for that parabola.
Thanks Found 2 solutions by stanbon, richwmiller:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! What is the focus point of y= 1/4x^2+2?
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Convert the equation to vertex form:
(1/4)(x^2) = y-2
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(x-2)^2 = 4(y-2)
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Vertex at (2,2)
Parabola opens up so focus is above the vertex.
4p = 4
p = 1
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Focus = (2,3)
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Cheers,
Stan H.
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You can put this solution on YOUR website! y= 1/4x^2+2
(1/4)(x^2)=y-2
(x)^2 = 4(y-2)
Vertex at (0,2)
Parabola opens up so focus is above the vertex.
4p = 4
p = 1
----
Focus = (0,3)
(