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| Question 293143:  Cyril invested part of 185 000 at 7% and the rest at 9. If the interest from the 9% investment in 1450 more than the interest earned at the 7% investment. How much did he invest at the 9% rate?
 Answer by checkley77(12844)
      (Show Source): 
You can put this solution on YOUR website! .09X=.07(185,000-X)+1,450 .09X=12,950-.07X+1,450
 .09X+.07X=12,950+1,450
 .16X=14,400
 X=14,400/.16
 X=90,000 ANOUNT INVESTED @ 9%.
 185,000-90,000=95,000 INVESTED @ 7%
 PROOF:
 .09*90,000=.07*95,000+1,450
 8,100=6,650+1,450
 8,100=8,100
 
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