SOLUTION: Find the center and radius of the circle {{{ x^2+6x+y^2-2y+6=0}}}

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Question 293080: Find the center and radius of the circle
+x%5E2%2B6x%2By%5E2-2y%2B6=0
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+6x+y^2-2y+6=0
you need to complete the square twice
6/2=3
3^2=9
2/2=1
1^2=1
x^2+6x+9+y^2-2y+1=-6+9+1
x^2+6x+9+y^2-2y+1=-6+9+1
(x+3)^2+(y-1)^2=4
center (-3,1)
radius 2