SOLUTION: I've worked hours on this question and can't figure it out. Can u please help? Thanks! *In printing an article of 48,000 words, a printer decides to use two sizes of type. Using

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: I've worked hours on this question and can't figure it out. Can u please help? Thanks! *In printing an article of 48,000 words, a printer decides to use two sizes of type. Using      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 293034: I've worked hours on this question and can't figure it out. Can u please help? Thanks!
*In printing an article of 48,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contains 1,800 words. Using a smaller type, a page contains 2,400 words. The article is allotted 21 full pages in a magazine. How many pages must be in smaller type? ___________

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let S be the number of smaller font pages and L be the number of larget font pages.
There are 21 total pages.
1.S%2BL=21
The number of words per page is 1800 and 2400 respectively. The total number of words is 48000.
2400%2AS%2B1800%2AL=48000
24S%2B18L=480
2.4S%2B3L=80
Now use eq. 1 to get S in terms of L and substitute,
S%2BL=21
S=21-L
.
.
.
4S%2B3L=80
4%2821-L%29%2B3L=80
84-4L%2B3L=80
-L=-4
L=4
Then from eq. 1,
S=21-L
S=21-4=17
17 small font pages and 4 large font pages.