SOLUTION: A real tricky one for me. The question reads...The lengths of the sides of a quadralateral are consecutive even integers. Twice the length of the shortest side plus the length of

Algebra ->  Expressions-with-variables -> SOLUTION: A real tricky one for me. The question reads...The lengths of the sides of a quadralateral are consecutive even integers. Twice the length of the shortest side plus the length of      Log On


   

Question 29274: A real tricky one for me. The question reads...The lengths of the sides of a quadralateral are consecutive even integers. Twice the length of the shortest side plus the length of the longest side is 120 inches. Find the lengths of the four sides. I began with 2x + y =120 and I know that this is only to figure two of the sides. I'm unsure of where to begin from here. thanks for your help.
Answer by atif.muhammad(135) About Me  (Show Source):
You can put this solution on YOUR website!


shortest side = x, 
second side = (x+2) 
third side = (x+4) 
longest side = (x+6) 
(They are consecutive even integers)

Twice the length of the shortest side + length of the longest side = 120 inch
            2x                                  +                  x+6                        = 120

Expand the brackets

2x + x + 6 = 120

3x + 6 = 120

3x = 114

x = 38 inches

Shortest side = 38 inch
Second side = 40 inch (x+2)
Third side = 42 inch (x+4)
Longest side = 44 inch (x+6)