SOLUTION: Use the sine and cosine addition formulæ to show that, for suitable x and y,
{{{tan(x+y)=(tan(x) + tan(y)) /(1-tan(x)tan(y))}}}
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-> SOLUTION: Use the sine and cosine addition formulæ to show that, for suitable x and y,
{{{tan(x+y)=(tan(x) + tan(y)) /(1-tan(x)tan(y))}}}
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