SOLUTION: I need to find the quotient using long division.
9a^3-3a^2-3a+4 divided by 3a+2 I understand the first step
9a^3/3a= 3a^2
then 3a^2(3a+2)= 9a^3+6a^2 leaving a balance of -9-3a+4
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-> SOLUTION: I need to find the quotient using long division.
9a^3-3a^2-3a+4 divided by 3a+2 I understand the first step
9a^3/3a= 3a^2
then 3a^2(3a+2)= 9a^3+6a^2 leaving a balance of -9-3a+4
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Question 292594: I need to find the quotient using long division.
9a^3-3a^2-3a+4 divided by 3a+2 I understand the first step
9a^3/3a= 3a^2
then 3a^2(3a+2)= 9a^3+6a^2 leaving a balance of -9-3a+4
then -9/3a=-3a which brings me to
-3a(3a+2)=-9a^2-6a which leaves a balance of a^2+3a+4
here is where I am confused
if I perform a^2/3a I think the result is 1/3a
The answers state that quotient of 9a^3-3a^2-3a+4 divided by 3a+2 is equal to
3a^2-3a+1+ (2 over 3a+2) I am unsure how they solve the last expression. Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website!
3 a | + | 2 | | 3 a^2 | - | 3 a | + | 1
9 a^3 | - | 3 a^2 | - | 3 a | + | 4
9 a^3 | + | 6 a^2 | | | |
| | -9 a^2 | - | 3 a | |
| | -9 a^2 | - | 6 a | |
| | | | 3 a | + | 4
| | | | 3 a | + | 2
| | | | | | 2
the book answer is correct
