Question 29223: Can you please tell me how to solve equations such as:
x2-x-20 / x2+4x-5
_______ _______
5x-25 x2-25
(x2 means x squared) Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! ((x^2-x-20)/(5x-25))/((x^2+4x-5)/(x^2-25))
that is the same equation as multiplying by the recipricol
((x^2-x-20)/(5x-25))*((x^2-25)/(x^2+4x-5))
In the next step, i am going to simplify the equations
([(x-5)(x+4)]/[5(x-5)])*([(x-5)(x+5)]/[(x+5)(x-1)])
after deleting some of the extra polynomials, the answer is:
((x-5)(x+4))/(5(x-1))
(