SOLUTION: ZACHARIAS HAS A TOTAL OF 65 COINS, ALL OF WHICH ARE EITHER DIMES OR NICKELS. THE TOTAL VALUE OF THE COINS IS $5.80. FIND THE NUMBER OF EACH TYPE OF COIN.

Algebra ->  Customizable Word Problem Solvers  -> Evaluation -> SOLUTION: ZACHARIAS HAS A TOTAL OF 65 COINS, ALL OF WHICH ARE EITHER DIMES OR NICKELS. THE TOTAL VALUE OF THE COINS IS $5.80. FIND THE NUMBER OF EACH TYPE OF COIN.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 292142: ZACHARIAS HAS A TOTAL OF 65 COINS, ALL OF WHICH ARE EITHER DIMES OR NICKELS. THE TOTAL VALUE OF THE COINS IS $5.80. FIND THE NUMBER OF EACH TYPE OF COIN.
Found 2 solutions by stanbon, richwmiller:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
ZACHARIAS HAS A TOTAL OF 65 COINS, ALL OF WHICH ARE EITHER DIMES OR NICKELS. THE TOTAL VALUE OF THE COINS IS $5.80. FIND THE NUMBER OF EACH TYPE OF COIN.
-------------
Equations:
Quantity Eq:::: d + n = 65
Value Eq::::::10d+ 5n = 580 cents
------------------------------------
Multiply thru the Quantity Eq. by 10; subtract and solv for "n":
10d + 10n = 650
10d + 5n = 580
-----------------------
5n = 70
n = 14 (# of nickels)
---
Substitute and solve for "d":
d + 14 = 65
d = 51 (# of dimes)
=================================
Cheers,
Stan H.
=================================

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Please use normal letters. All caps is shouting.