SOLUTION: y=x^2+8x+3/√x √=square root Ans: y'=3x^2+8x-3/2x^3/2

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Question 292134: y=x^2+8x+3/√x

√=square root
Ans: y'=3x^2+8x-3/2x^3/2
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2+8x+3/√x
√=square root
Ans: y'=3x^2+8x-3/2x^3/2
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Form:
If y = f/g
Then y' = (gf'-fg')/g^2
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Your Problem:
y' = [sqrt(x)*(2x+8)-(x^2+8x-2)*(1/2sqrt(x)]/x
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Cheers,
Stan H.
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