Question 291678: Please help to answer the follwing question.
If the profit function for a commodity is p=6400x-18x^2-(1/3)x^3-40,000 dollars, selling how many units, x, will result in a maximum profit? Find the maximum profit.
(I am having troublw getting past this:
p'=6400-36x-x^2=0
Thanks!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If the profit function for a commodity is p=6400x-18x^2-(1/3)x^3-40,000 dollars, selling how many units, x, will result in a maximum profit? Find the maximum profit.
p'(x) = 6400 - 36x - x^2
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Solve x^2 + 36x + 6400 = 0
(x+100)(x-64) = 0
Poxitive solution:
x = 64
p(64) = $208,491
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Cheers,
Stan H.
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