SOLUTION: Find three consecutive odd integers such that three times the third is 7 more than the sum of the other two.

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Question 291612: Find three consecutive odd integers such that three times the third is 7 more than the sum of the other two.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive odd integers such that three times the third is 7 more than the sum of the other two.
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equality:
3(2x+3)= 4x+7
6x+9 = 4x+7
2x = -2
x = -1
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1st: 2x-1 = -3
2nd: 2x+1 = -1
3rd: 2x+3 = 1
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Cheers,
Stan H.