SOLUTION: suppose you are playing a game in which 2 fair die are rolled. you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of la
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-> SOLUTION: suppose you are playing a game in which 2 fair die are rolled. you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of la
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Question 291606: suppose you are playing a game in which 2 fair die are rolled. you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of landing on the finish or rolling again. explain in detail.
You can put this solution on YOUR website! suppose you are playing a game in which 2 fair die are rolled.
you need a 9 to land on finish by an exact count or a 3 to land on "roll again" space. what is the probability of landing on the finish or rolling again. explain in detail.
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Rule: P(A or B) = P(A) + P(B) - P(A and B)
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Your Problem: The two events are mutually exclusive
so P(A and B) is zero.
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Ways to get a 9: 6/3;5/4;4/5;3/6
P(get a 9) = 4/36
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Ways to get a 3: 2/1;1/2
P(get a 3) = P(2/36)
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Ans: P(9 or 3) = 4/36 + 2/36 = 6/36 = 1/6
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Cheers,
Stan H.
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