SOLUTION: Problem solving by Quadratic equations: Find two numbers whose product is 57, and one of the numbers is 5 less than eight times the other number. Thank you
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Question 291318: Problem solving by Quadratic equations: Find two numbers whose product is 57, and one of the numbers is 5 less than eight times the other number. Thank you Found 2 solutions by checkley77, killermen:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! xy=57
x=8y-5
(8y-5)y=57
8y^2-5y-57=0
(8y+19)(y-3)=0
y-3=0
y=3 ans.
x=8*3-5
x=24-5
x=19 ans.
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8y+19=0
8y=-19
y=-19/8 ans.
x=8(-19/8)-5
x=-19-5
x=-24 ans.
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