Question 291147: you have 3 nickels, 2 dimes, and 5 quarters and choose three of these in succession. find the probability of selecting 1 nickel, 1 dime, and 1 quarter, in any order with replacement.
Answer by Edwin McCravy(20063)   (Show Source):
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Any of the 3! or 6 orders NDQ, NQD, DNQ, DQN, QND, QDN will be successful.
The number of ways any one of these 6 orders can be selected is 3*2*5 or
30 ways. So there are 6*30 or 180 possible successful selections.
The number of ways any three coins can be selected, since it is with
replacement is 10*10*10 or 1000.
Therefore the desired probability is  which reduces to 9/500,
or if expressed as a decimal is 0.018.
Edwin
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