Question 291123: Hello
I'm really stuck on this question and would be very grateful if you could help me out.
QUESTION:Find the points of intersection of the line y=5x+13 with the circle
I'm not really sure how to approanch this question but have been attempting to solve it almost like a simultaneous equation by substitution:
This eventually gets me down to the quadratic:

simplified to
This is all probably wrong but even if I am right I don't know where to go from here...
Please help!
Thanks ever so much,
From Katie
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! You're on the right track. I'll start where you left off.
Let's solve by use of the quadratic formula.
| Solved by pluggable solver: Quadratic Formula |
Let's use the quadratic formula to solve for x:
Starting with the general quadratic

the general solution using the quadratic equation is:

So lets solve ( notice , , and )
Plug in a=13, b=65, and c=78
Square 65 to get 4225
Multiply to get 
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this solver)
Multiply 2 and 13 to get 26
So now the expression breaks down into two parts
or 
Lets look at the first part:

Add the terms in the numerator
Divide
So one answer is

Now lets look at the second part:

Subtract the terms in the numerator
Divide
So another answer is

So our solutions are:
or 
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Now plug each of these solutions into to find the corresponding 'y' coordinates of the intersections.
So when , then giving us the point (-2,3)
Also, when , then giving us the point (-3,-2)
So the two points of intersection are (-2,3) and (-3,-2)
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