Question 291106: John has 36 coins that are nickels and dimes. If the value of the coins is $2.90, how many coins of each type does he have? Answer by brucewill(101) (Show Source):
You can put this solution on YOUR website! Let x = # of nickels
Therefore, 36 - x = # of dimes.
5x + 10(36 - x) = 290
5x + 360 - 10x = 290
-5x = -70 nickels
36-14 = 22 dimes
Check:
0.05 * 14 = 0.70; 0.10 * 22 = $2.20, Total $2.90. OK.