SOLUTION: Solve using the rational root theorem x^4-5x^3+11x^2-25x+30 My Work: p/q= 30/1 30= +- 1, 2, 3, 5, 6, 10, 15, and 30 1= +- 1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve using the rational root theorem x^4-5x^3+11x^2-25x+30 My Work: p/q= 30/1 30= +- 1, 2, 3, 5, 6, 10, 15, and 30 1= +- 1       Log On


   



Question 290969: Solve using the rational root theorem x^4-5x^3+11x^2-25x+30
My Work:
p/q= 30/1 30= +- 1, 2, 3, 5, 6, 10, 15, and 30
1= +- 1
possible rational roots = 1, 2 ,3, 5, 6, 10, 15, 30
I have discovered that 3 is a root. I used synthetic division and got a remainder of zero. Now what do i do?

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Yes it is.
What did you get after synthetic division?
x^3-2 x^2+5x-10
1,2,5,10 right.
Do the same thing and find the other real root.
After this you will get a quadratic equation and you can use the quadratic formula to find the complex roots or factor it.
You should be able to factor it by grouping which is unFOILing.