Any help would be great.
Ans=63/5 x^2/5 -10x Found 2 solutions by dabanfield, Edwin McCravy:Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! f(x)=9x^7/5-5x^2+10^4
Using the rules that the derivative of a sum of functions is the sum of the derivatives, the derivative of x^n = n*x^(n-1), the derivative of a constant times a function is the constant times the derivative of the function and the derivative of a constant (like 10^4) is 0:
f'(x) = 9*(7/5)*x^(7/5 - 1) - 5*2*x^(2-1) + 0
f'(x) = 63*x^(2/5) - 10*x^1
f'(x) = 63x^(2/5) - 10x
,
Since we have:
Since we can write the as
a multiple of a power of
Now all the terms are multiples of powers of x.
Learn the rule for taking the derivative of a
multiple of a power of x:
1. Multiply the exponent by the coefficient.
2. Subtract 1 from the exponent
For the first term ,
1. Multiply the exponent by the coefficient ,
getting .
2. Subtract 1 from the exponents
So the derivative of the first term is
For the second term ,
1. Multiply the exponent by the coefficient ,
getting .
2. Subtract 1 from the exponents
So the derivative of the second term is
or
For the third term ,
1. Multiply the exponent by the coefficient ,
getting .
2. Subtract 1 from the exponents
So the derivative of the third term is
or .
[You can also just learn that the derivative of a constant is 0)
Therefore the derivative of
is
or dropping the 0:
Edwin
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