SOLUTION: How do you: Find the other zeroes of f(x)= x^3+5x^2-18x-72 given that one zero is 4?
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Question 290648
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How do you: Find the other zeroes of f(x)= x^3+5x^2-18x-72 given that one zero is 4?
Answer by
richwmiller(17219)
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divide that equation by (x-4) and you will get a quadratic equation.But with any luck you can factor it. If not the quadratic formula can find the other zeros
This one can be factored
(x-4)*(x+3) (x+6)