SOLUTION: The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the legnth and width of the rectangle.
I think the equation is
(L-4) * L = 9
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-> SOLUTION: The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the legnth and width of the rectangle.
I think the equation is
(L-4) * L = 9
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Question 290564: The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the legnth and width of the rectangle.
I think the equation is
(L-4) * L = 96 CM ^2
L^2 - 4L=96
How do I get rid of the 4L? So I can take the square root of the number on the right? Is the second step of the formula correct?my formalus
You can put this solution on YOUR website! The width of a rectangle is 4 cm less than its length. The area of the rectangle is 96 CM ^2. Find the length and width of the rectangle.
I think the equation is
(L-4) * L = 96 CM ^2
L^2 - 4L=96
How do I get rid of the 4L?
Subtract 96 from both sides:
L^2-4L-96 = 0
(L+8)(L-12) = 0
Positive solution:
Length = 12 cm
Width = L-4 = 8 cm
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Cheers,
Stan H.
So I can take the square root of the number on the right? Is the second step of the formula correct?my formalus
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