SOLUTION: Find 3 consecutive odd numbers where the product of the smaller two numbers is 28 less than the square of the largest number?

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Question 290554: Find 3 consecutive odd numbers where the product of the smaller two numbers is 28 less than the square of the largest number?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, x+2 & x+4 be the 3 consecutive odd numbers.
x(x+2)=(x+4)^2-28
x^2+2x=x^2+8x+16-28
x^2-x^2+2x-8x=16-28
-6x=-12
x=-12/-6
x=2 ans.
Proof:
2(2+2)=(2+4)^2-28
2*4=6^2-28
8=36-28
8=8