You can put this solution on YOUR website! One number is 12 more than another. The sum of the smaller number and twice the larger number is 39. Find the larger number.
Let the larger number be L and
let the smaller number be S
One number is 12 more than another
That is L= S+12 ----(1)
The sum of the smaller number and twice the larger number is 39.
That is (S+2L) = 39 ----(2)
(1) implies S= L-12 ---(*)
Putting (*) in (2)
S+2L=39
(L-12)+2L = 39
(L+2L)-12 = 39
3L-12 = 39
3L = 39+12
3L= 51
L=51/3 = 17
Therefore the larger number is 17
Verification:From (*), S = L-12 = 17 -12 = 5
And S+2L = 5 +2X17 = 5+34 = 39 which is correct.
Therefore our answer is correct.
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